how to locate root 10 on the number line??
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for √10, mark a point A on the number line such that OA = 3 and draw a line AB perpendicular to the number line such that AB = 1
OB2= OA2+AB2
= OB2= (3)^2 + (1)^2
=> OB = √10 (by pythagorus theorem)
With center at O and radius = OB = √10, cut an arc at C on the number line
=> OC = √10.
OB2= OA2+AB2
= OB2= (3)^2 + (1)^2
=> OB = √10 (by pythagorus theorem)
With center at O and radius = OB = √10, cut an arc at C on the number line
=> OC = √10.
ilml:
root 10=square of 3 and square of 1
HOPE IT HELPED :)
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