the ratio of the volumes of two spheres is 27:8. find the ratio of their surface areas.
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Hi,
Let the radii of the two Spears are
R and r,
Volumes of two Spears are V ,v
According to the problem given ,
V / v = 27 / 8
( 4/3 πR³ )/ ( 4/3πr³ ) = 27 / 8
After cancellation,
R³ / r³ = 3³ / 2³
(R / r )³ = ( 3 / 2 )³
R / r = 3 / 2 ------( 1 )
Let the ratios of the
Curved surface area of the
Spears = ( 4πR² ) / ( 4πr² )
= R² / r²
= ( R / r )²
= ( 3 / 2 )²
= 9 / 4
Therefore ,
Ratios of the curved surface area
of the Spears = 9 : 4
I hope this helps you.
:)
Let the radii of the two Spears are
R and r,
Volumes of two Spears are V ,v
According to the problem given ,
V / v = 27 / 8
( 4/3 πR³ )/ ( 4/3πr³ ) = 27 / 8
After cancellation,
R³ / r³ = 3³ / 2³
(R / r )³ = ( 3 / 2 )³
R / r = 3 / 2 ------( 1 )
Let the ratios of the
Curved surface area of the
Spears = ( 4πR² ) / ( 4πr² )
= R² / r²
= ( R / r )²
= ( 3 / 2 )²
= 9 / 4
Therefore ,
Ratios of the curved surface area
of the Spears = 9 : 4
I hope this helps you.
:)
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