How to middle split 6 x square minus 3 minus 7 x
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Hi Mate !!
Given Equation :- 6x² - 3 - 7x
• To Solve by middle term the Equation should be in the form of ax² + bx + c
So, arranging them in this order.
6x² - 7x - 3
• Multiply the coefficient of x² by the constant term and take the LCM of resultant.
6 × 3 = 18
LCM :- 2 × 3 × 3
• Now , either by sub or by adding we have to get 7 in middle.
6x² - 7x - 3
6x² - 9x + 2x - 3
3x ( 2x - 3 ) + 1 ( 2x - 3 )
( 3x + 1 ) ( 2x - 3 )
Is the factorization of the Equation !!
Given Equation :- 6x² - 3 - 7x
• To Solve by middle term the Equation should be in the form of ax² + bx + c
So, arranging them in this order.
6x² - 7x - 3
• Multiply the coefficient of x² by the constant term and take the LCM of resultant.
6 × 3 = 18
LCM :- 2 × 3 × 3
• Now , either by sub or by adding we have to get 7 in middle.
6x² - 7x - 3
6x² - 9x + 2x - 3
3x ( 2x - 3 ) + 1 ( 2x - 3 )
( 3x + 1 ) ( 2x - 3 )
Is the factorization of the Equation !!
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