Question

how to prove 6+root 2

Answer 1

$6 + \sqrt{2} = x$
$\sqrt{2} = x - 6$
$2 = {(x - 6)}^{2}$

Answer 2

i think you are asking to prove it irrational so here your answer is.. .


let 6+root2 be in p/q form
then shift 6 on the rhs you will have an eq like this: root2=p-6q/q
then irrational is not equal to rational
contradiction arises and hence proved that our assumption was wrong 6+ root2 is irrational