how to solve quadratic polynomial inequality question.... pls explain by solving the given question step by step for x :
i would be active in the comment section... and if you make all my doubts clear then i would definitely mark you the BRAINLIEST.....
But, pls don't give unwanted answers...
if you feel confident enough to resolve my doubts then only answer....pls....
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hey mate
here you go...
while solving the quadratic inequality,you need to care about the sign of inequality.
for example:(as per your question)
x²-4<=0
(x-2)(x+2)<=0
now here you see the sign is less than 0,we means the product should be negative.(for which one of components of the multiplication should be negative)
for example=
-6=-3*2 or -6=3*-2
(in both cases one has be -ve)
so ,
case 1:
when (x-2) is -ve,then (X+2) should be +ve.
(x-2)<=0 and (X+2)>=0
X<=2 and X>=-2
-2<=X<=2
case 2: when (x-2) is +ve,then (X+2) should be -ve.
(x-2)>=0 and (X+2)<=0
X>=2 and X<=-2
this was the method of solving the quadratic inequality..
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ojhaanshu3321:
then kunal you mean i should attempt for both the cases
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