Question

How to solve: sec A - 1/sec A +1= 1-cos A/1+ cos A

Answer 1

$LHS = \frac{sec A - 1}{sec A + 1} \\= \frac{\frac{1}{cosA } - 1 }{ \frac{1}{cosA} + 1 } \\= \frac{ \frac{(1-cosA)}{cosA}}{\frac{(1+cosA)}{cosA}}\\= \frac{1-cosA}{1+cosA} \\= RHS$

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