Question

One of to the two digits of a two digit is three times the other digit, if you interchange the of its two digit number and add the resulting number to the original number, you get 88.what is original number.? ​

Answer 1

❏ Solution:-

Is in the attachment

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Answer 2

AnswEr :

62.

$\bf{\green{\underline{\underline{\sf{Given\::}}}}}$

One of the two digits of a two digit is three times the other digit, if you interchange the of it's two digit number and add the resulting number to the original number you get 88.

$\bf{\red{\underline{\underline{\sf{To\:find\::}}}}}$

The original number.

$\bf{\purple{\underline{\underline{\bf{Explanation\::}}}}}$

Let the ten's place be 3r

Let the one's place be r

$\underbrace{\bf{Original\:number\:=10(3r)+r}}\\\\\underbrace{\bf{Reversed\:number\:=10(r)+3r}}$

$\bf{\red{\underline{\underline{\tt{A.T.Q.\::}}}}}$

$\dashrightarrow\tt{10(3r)+r+10(r)+3r=88}\\\\\\\dashrightarrow\tt{30r+r+10r+3r=88}\\\\\\\dashrightarrow\tt{31r+13r=88}\\\\\\\dashrightarrow\tt{44r=88}\\\\\\\dashrightarrow\tt{r=\cancel{\dfrac{88}{44} }}\\\\\\\dashrightarrow\tt{\purple{r=2}}$

$\therefore\bf{\orange{\underline{\sf{The\:original\:number=10(3r)+r=10*3(2)+2=60+2=62.}}}}$