Math, asked by anushreeganguly2015, 9 months ago

How to solve sum no 8 using unitary method?

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Answers

Answered by aditya012
3

Answer:

360

Step-by-step explanation:

work left = 3/4

days left = 7

people =?

280 ppls 3 day work = 1/4

280 ppls 1 day work = 1/12

1 persons 1 day work = 1/3360

1 persons 7 day work= 7 / 3360

Total work left = 3/4

Ppl required =( 3/4) / ( 7/3360)

= 360

Answered by RvChaudharY50
34

|| ✰✰ ANSWER ✰✰ ||

It is given that , 280 Heads of People can complete The work in 10 days.

Also Given That, in 3 days These 280 heads of People completed Only (1/4)th of the Total work.

That Means we can say That :- (1 - 1/4) = (3/4)th of The work is Still Left to be done.

And, we have Days Left now = 10-3 = 7 days.

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Lets assume That, now we have X heads of People .

So, Now, with Work out Method we can say That :-

→ if 280 Workers complete (1/4)th of The work in 3 days Than how many workers will complete (3/4)th of the work in 7 days.

→ (M1 * D1 /W1) = (M2 * D2)/(W2)

Putting values now , we get :-

→ ( 280 * 3) / (1/4) = ( X * 7) /(3/4)

Cross - Multiply,

→ 280 * 3 * (3/4) = X * 7 * (1/4)

→ 280 * 9 = 7X

→ 7X = 280 * 9

Dividing by 7 both sides

→ X = 40*9

→ X = 360 Heads of People .

So,

→ Extra Heads of People Required = 360 - 280 = 80 Heads of People.

Hence, 80 More Heads of People Required To complete The work in Time.

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