Question

How to solve this..?

Answer 1

The radius of the semicircle seems to be 28/2cm = 14cm

and
the angle subtended by the semicirlce her is 90°.

The height of the triangle = radius os semicire. = 14 cm.

and the base is 28cm.

Area of shaded region = area of semicircle - area of the triangle,

Therefore,

$[tex](\frac{1}{2} \times \frac{22}{7} \times 14 \times 14 )- ( \frac{1}{2} \times 14 \times 28) \\ \\ = \frac{1}{2} \times 14( \frac{22}{7} \times 14 - 28) \\ = 7(16) \\ 112 {cm}^{2}$

Therefore option ( D ) is the correct one.