How to solve this? Answer is given
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In the figure
Angle PCB= 40 (angle of reflection is equal to angle of incidence)
Angle PCO=90 (Normal)
Angle ACA=90-40=50
=> Angle OCA=80
If a normal is drawn at A then each incident and refracted angle would be 10 (90-80)
=> Angle CAB = 20
Therefore Angle x= 80+20= 100 (by exterior angle property)
Note: Refer the figure
Angle PCB= 40 (angle of reflection is equal to angle of incidence)
Angle PCO=90 (Normal)
Angle ACA=90-40=50
=> Angle OCA=80
If a normal is drawn at A then each incident and refracted angle would be 10 (90-80)
=> Angle CAB = 20
Therefore Angle x= 80+20= 100 (by exterior angle property)
Note: Refer the figure
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Anonymous:
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