Question

How to solve this equation?
${x}^{2} = 5 + x$
​

Answer 1

Answer:

$x = \frac{1 + \sqrt{21} }{2} \\ x = \frac{1 - \sqrt{21} }{2}$

if you need any explanation, please let me know....

Answer 2

Answer:

x1=0 x2=−5. Explanation: x2+5x=0 x(x+5)=0. By the null factor law either x or x+5 must be equal to 0 . x1=0 x2=−5.