Math, asked by aartimuku2411, 5 months ago

how to solve this euation
840/x - 840/x+10=2

Answers

Answered by midathanabhavani297
0

Answer:

How to solve your question

Your question is

8

4

0

1

8

4

0

+

1

0

=

2

\frac{840}{x}-1 \cdot \frac{840}{x}+10=2

x840−1⋅x840+10=2

Solve

1

Combine multiplied terms into a single fraction

8

4

0

1

8

4

0

+

1

0

=

2

\frac{840}{x}-1 \cdot \frac{840}{x}+10=2

x840−1⋅x840+10=2

8

4

0

+

1

8

4

0

+

1

0

=

2

\frac{840}{x}+\frac{-1 \cdot 840}{x}+10=2

x840+x−1⋅840+10=2

2

Multiply the numbers

8

4

0

+

1

8

4

0

+

1

0

=

2

\frac{840}{x}+\frac{{\color{#c92786}{-1}} \cdot {\color{#c92786}{840}}}{x}+10=2

x840+x−1⋅840+10=2

8

4

0

+

8

4

0

+

1

0

=

2

\frac{840}{x}+\frac{{\color{#c92786}{-840}}}{x}+10=2

x840+x−840+10=2

3

Subtract

1

0

10

10

from both sides of the equation

8

4

0

+

8

4

0

+

1

0

=

2

\frac{840}{x}+\frac{-840}{x}+10=2

x840+x−840+10=2

8

4

0

+

8

4

0

+

1

0

1

0

=

2

1

0

\frac{840}{x}+\frac{-840}{x}+10{\color{#c92786}{-10}}=2{\color{#c92786}{-10}}

x840+x−840+10−10=2−10

4

Simplify

Subtract the numbers

Subtract the numbers

again

8

4

0

+

8

4

0

=

8

\frac{840}{x}+\frac{-840}{x}=-8

x840+x−840=−8

5

Multiply all terms by the same value to eliminate fraction denominators

8

4

0

+

8

4

0

=

8

\frac{840}{x}+\frac{-840}{x}=-8

x840+x−840=−8

(

8

4

0

+

8

4

0

)

=

(

8

)

x(\frac{840}{x}+\frac{-840}{x})=x(-8)

x(x840+x−840)=x(−8)

6

Simplify

Distribute

Cancel multiplied terms that are in the denominator

Cancel multiplied terms that are in the denominator

again

Subtract the numbers

Re-order terms so that constants are on the left

0

=

8

0=-8x

0=−8x

7

Divide both sides of the equation by the same term

0

=

8

0=-8x

0=−8x

0

8

=

8

8

\frac{0}{{\color{#c92786}{-8}}}=\frac{-8x}{{\color{#c92786}{-8}}}

−80=−8−8x

8

Simplify

Cancel terms that are in both the numerator and denominator

0

=

Answered by revathigerigi
0

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