how to solve this euation
840/x - 840/x+10=2
Answers
Answer:
How to solve your question
Your question is
8
4
0
−
1
⋅
8
4
0
+
1
0
=
2
\frac{840}{x}-1 \cdot \frac{840}{x}+10=2
x840−1⋅x840+10=2
Solve
1
Combine multiplied terms into a single fraction
8
4
0
−
1
⋅
8
4
0
+
1
0
=
2
\frac{840}{x}-1 \cdot \frac{840}{x}+10=2
x840−1⋅x840+10=2
8
4
0
+
−
1
⋅
8
4
0
+
1
0
=
2
\frac{840}{x}+\frac{-1 \cdot 840}{x}+10=2
x840+x−1⋅840+10=2
2
Multiply the numbers
8
4
0
+
−
1
⋅
8
4
0
+
1
0
=
2
\frac{840}{x}+\frac{{\color{#c92786}{-1}} \cdot {\color{#c92786}{840}}}{x}+10=2
x840+x−1⋅840+10=2
8
4
0
+
−
8
4
0
+
1
0
=
2
\frac{840}{x}+\frac{{\color{#c92786}{-840}}}{x}+10=2
x840+x−840+10=2
3
Subtract
1
0
10
10
from both sides of the equation
8
4
0
+
−
8
4
0
+
1
0
=
2
\frac{840}{x}+\frac{-840}{x}+10=2
x840+x−840+10=2
8
4
0
+
−
8
4
0
+
1
0
−
1
0
=
2
−
1
0
\frac{840}{x}+\frac{-840}{x}+10{\color{#c92786}{-10}}=2{\color{#c92786}{-10}}
x840+x−840+10−10=2−10
4
Simplify
Subtract the numbers
Subtract the numbers
again
8
4
0
+
−
8
4
0
=
−
8
\frac{840}{x}+\frac{-840}{x}=-8
x840+x−840=−8
5
Multiply all terms by the same value to eliminate fraction denominators
8
4
0
+
−
8
4
0
=
−
8
\frac{840}{x}+\frac{-840}{x}=-8
x840+x−840=−8
(
8
4
0
+
−
8
4
0
)
=
(
−
8
)
x(\frac{840}{x}+\frac{-840}{x})=x(-8)
x(x840+x−840)=x(−8)
6
Simplify
Distribute
Cancel multiplied terms that are in the denominator
Cancel multiplied terms that are in the denominator
again
Subtract the numbers
Re-order terms so that constants are on the left
0
=
−
8
0=-8x
0=−8x
7
Divide both sides of the equation by the same term
0
=
−
8
0=-8x
0=−8x
0
−
8
=
−
8
−
8
\frac{0}{{\color{#c92786}{-8}}}=\frac{-8x}{{\color{#c92786}{-8}}}
−80=−8−8x
8
Simplify
Cancel terms that are in both the numerator and denominator
0
=