Question

how to solve this problem

Answer 1

HEY MATE HERE IS YOUR ANSWER

GIVEN THAT ➡️RAY AZ BISECTS ANGLE DAB AND ANGLE PCB THAT IS

ANGLE DAC = ANGLE BAC

AND

ANGLE BCA = ANGLE DCA

SOLUTION ➡️

A) ). Q)) TO STATE THREE PAIRS OF EQUAL PARTS IN TRIANGLE BAC AND TRIANGLE DAC

ANS ➡️ WE KNOW THAT

ANGLE DAC = ANGLE BAC ( GIVEN ) ------ PART (1) OF TRIANGLES

SIMILARLY

ANGLE DCA = ANGLE BCA ( GIVEN ) ------ PART (2) OF TRIANGLES

FINALLY

LINE SEGMENT AC = AC. ( COMMON ). ------ PART (3) OF TRIANGLES


NOW FROM PART (1) , (2) AND (3) WE HAVE THREE EQUAL PARTS IN TRIANGLE BAC AND TRIANGLE DAC.

THEREFORE Q .A IS SOLVED

B)) NOW IN Q.B WE NEED

TO PROVE ➡️THAT TRIANGLE BAC CONGRUENT TO TRIANGLE DAC .


PROOF ➡️IN TRIANGLE BAC AND DAC


ANGLE DAC = BAC. ( GIVEN ) ---- EQ (1) ANGLE

SIDE AC = CA. ( COMMON ) ----- EQ (2) SIDE

AND

ANGLE DCA = BCA. ( GIVEN ) ----- EQ (3) ANGLE

SO NOW FROM EQ 1 , 2 AND 3 AND USING A.S.A CONGRUENCE RULE ( ANGLE INCLUDED SIDE ANGLE )

TRIANGLE -

BAC CONGRUENT TO TRIANGLE DAC

$hence \: proved \: question \: b \:$
NOW MOVING TWO QUESTION C ))

C)) TO PROVE ➡️AB = AD

PROOF ➡️NOW WE KNOW THAT

TRIANGLE BAC CONGRUENT TO TRIANGLE DAC. ( AS PROVED ABOVE )

SO FROM (C.P.C.T ). ( CORRESPONDING PARTS OF CONGRUENT TRIANGLE )

THEREFORE WE HAVE

AB = AD. ( BY CPCT )

HENCE PROVED THAT

AB = AD

NOW MOVING TO QUESTION D )))

Q D ))) TO PROVE ➡️CD = CB

PROOF ➡️ WE NOW THAT

TRIANGLE BAC CONGRUENT TO TRIANGLE DAC. ( PROVED ABOVE )

SO FROM CPCT WE HAVE

CD = CB. ( BY CPCT )

HENCE PROVED THAT

CD = CB.


HOPE IT'S HELPFUL !!!!

BE BRAINLY ☯️