how to solve this question:-
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Answered by
2
Answer.
Let the past age of son = x
Let the past age of father = 7x
So,
Present ages are x+5 and 7x+5
Future age of son = x+10
Future age of father = 7x+10
Given
7x+10 = 3*(x+10)
7x+10 = 3x+30
7x-3x = 30-10
4x = 20
x = 20/4
x = 5
7x = 35
x+5 = 10
7x+5 = 40
Answered by
1
Let the present ages of the father and his son be x and y respectively.
By the problem,
x-5 = 7(y-5)
=>x - 7y = - 30.... (1)
Also,
x +5 = 3(y+5)
=> x - 3y = 10...(2)
Therefore subtracting equation 1 from equation 2 we get,
-4y = - 40
=>y = 10 years
Substituting the value of y in equation 1, we get
x - 7(10)= - 30
=>x = 40
Ans : the man is presently 40 years old while his son is 10 years of age.
Hope this helps :)
By the problem,
x-5 = 7(y-5)
=>x - 7y = - 30.... (1)
Also,
x +5 = 3(y+5)
=> x - 3y = 10...(2)
Therefore subtracting equation 1 from equation 2 we get,
-4y = - 40
=>y = 10 years
Substituting the value of y in equation 1, we get
x - 7(10)= - 30
=>x = 40
Ans : the man is presently 40 years old while his son is 10 years of age.
Hope this helps :)
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