how to solve this question a rectangular courtyard is 18m72cm long and 13m20cm broad. it is paved with same size square tiles find the least possible no. of such tiles?
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Answer.
Given length of rectangular courtyard = 18 m 72 cm = 1872 cm
Width of rectangular courtyard = 13 m 20 cm = 1320 cm
To find the square tile of maximum side we take the HCG of 1872 and 1320 By Euclid’s division lemma
we have 1872 = 1320 × 1 + 552 1320 = 552 × 2 + 216 552 = 216 × 2 + 120 216 = 120
× 1 + 96 120 = 96 × 1 + 24 96 = 24 × 4 + 0 Hence the HCF is 24
Therefore maximum side of the square = 24 cm Number of tiles required = (Area of rectangular courtyard)
(Area of square tile) = (1872 × 1320)/(24 × 24) = 4290
Hence 4290 tiles are required
plz mark as brainliest dear
Given length of rectangular courtyard = 18 m 72 cm = 1872 cm
Width of rectangular courtyard = 13 m 20 cm = 1320 cm
To find the square tile of maximum side we take the HCG of 1872 and 1320 By Euclid’s division lemma
we have 1872 = 1320 × 1 + 552 1320 = 552 × 2 + 216 552 = 216 × 2 + 120 216 = 120
× 1 + 96 120 = 96 × 1 + 24 96 = 24 × 4 + 0 Hence the HCF is 24
Therefore maximum side of the square = 24 cm Number of tiles required = (Area of rectangular courtyard)
(Area of square tile) = (1872 × 1320)/(24 × 24) = 4290
Hence 4290 tiles are required
plz mark as brainliest dear
RAHUL366:
plz mark as brainliest
plz mark as brainliest dear sir
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area of rectangle = l*b
18 m 72 cm = 1872 cm
13m. 20 cm = 1320cm
=> 1872 * 1320 cm ^2
let no. of square tiles = x
area of one square tile = l^2
area of x square tiles = xl^2
18 m 72 cm = 1872 cm
13m. 20 cm = 1320cm
=> 1872 * 1320 cm ^2
let no. of square tiles = x
area of one square tile = l^2
area of x square tiles = xl^2
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