how to solve this question in substitution method<br />5x+3y=21;2x-y=4
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from first eqn u get
x=21-3y/(5)....................(a)
put this in second eqn
2(21-3y)/5 -y=4
2(21-3y)-5y=20
42-6y-5y=20
-11y=-22
y,=2
put this in (a)
x=(21-3y) /5
X!=(21-3(2))/5
x=3
x=21-3y/(5)....................(a)
put this in second eqn
2(21-3y)/5 -y=4
2(21-3y)-5y=20
42-6y-5y=20
-11y=-22
y,=2
put this in (a)
x=(21-3y) /5
X!=(21-3(2))/5
x=3
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