Question

how to solve this sum?​

Answer 1

Answer:

your answer is in the attachment

please mark as brainliest

follow me

Answer 2

Answer:

√29, 5 , 5√29

Step-by-step explanation:

x^2 + 1/(x^2) = 27

since ...(a-b)^2 = a^2 + b^2 - 2ab

[ x - 1/(x) ]^2 = x^2 + 1/(x^2) - 2 x (1/x)

now...[ x - 1/(x) ]^2 + 2 = 27

[ x - 1/(x) ]^2 = 25

[ x - 1/(x) ] = 5 .......….……....(1)

since...(a + b)^2 = (a -b)^2 4ab

(x + 1/x) ^2 = [ x - 1/(x) ]^2 + 4 x 1/x

(x + 1/x) ^2 = (5)^2 + 4

(x + 1/x) ^2 = 29

hence...(x + 1/x) = √29............(2)

since..a^2 - b^2 = (a+b)(a-b)

x^2 - (1/x)^2 = (x + 1/x) (x - 1/x)

x^2 - (1/x)^2 = 25√29….............(3)