how would pressure change if area is doubled keeping force constant
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Heya......!!!
____________________________
We know that Pressure = F / A
According to the question :-» Area is doubled keeping the force constant.
--» A = 2 A
=> P = F / A ( original Pressure )
New Pressure ( P' ) :-
•--» P' = F / 2A
--» P' = 1/2 ( F / A )
→ P' => 1/2 P
New pressure will be halved i.e ( 1/2 P )
================================
Hope It Helps You ☺
____________________________
We know that Pressure = F / A
According to the question :-» Area is doubled keeping the force constant.
--» A = 2 A
=> P = F / A ( original Pressure )
New Pressure ( P' ) :-
•--» P' = F / 2A
--» P' = 1/2 ( F / A )
→ P' => 1/2 P
New pressure will be halved i.e ( 1/2 P )
================================
Hope It Helps You ☺
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