Question

Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc. Calculate the
volume of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. (one mole of gas
occupies 22.7 L volume at STP atomic mass of Zn is 65.3u)​

Answer 1

Answer:

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Explanation:

Balanced reaction is:

Zn+2HCl→ZnCl2+H2 

Molar mass of Zn= 65.4 g/mol

thus 65.4 g of zinc liberates 1 mol i.e. 22.4 L hydrogen gas at STP

32.65 g of zinc will liberate:  

65.4

22.4

​  

×32.65=11.18L of hydrogen gas at STP