Question

hye...good morning..
please answer my question..

:)

Answer 1

Given line = 3x - 4y + 12 = 0.

Given that the line meets the x-axis.

The y-axis will be 0.

Now,

= > 3x - 4(0) + 12 = 0

= > 3x + 12 = 0

= > 3x = -12

= > x = -4.

Therefore the line 3x - 4y + 12 = 0 meets x-axis at (-4,0).

Given:

Equation of line = 3x + 5y - 15 = 0

= > 5y = 15 - 3x

= > y = -3/5x + 3


Slope of the line m1 = -3/5.

Slope of the required line m2 = -5/3.


Now,

Equation of the line:

y - y1 = m(x - x1)

= > y - 0 = -5/3(x + 4)

= > 3y = -5x - 20

= > 5x - 3y + 20 = 0.


Therefore the equation of the line = 5x - 3y + 20 = 0.



Hope this helps!