Question

Hypotenuse=15cm,Base=12cm,perpendicula

Answer 1

hey mate

h^2=b^2+ p^2

(15)^2=(12)^2+(p^)

225=144+p^2

225-144=p^2

81=p^2

√81=p

9=p

Answer 2

By pythagorous theorem

AC=15cm(hyp)

BC=12cm(base)

AB=?(perp)

AB^2=15^2-12^2

AB^2=225-144

AB^2=81

AB=®81

AB=9cm

perpendicular

=9cm

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