Question

hypotenuse is 32 base is 16 find perpendicular by Pythagoras ​

Answer 1

Answer:

$\sqrt{768}$

Step-by-step explanation:

${h}^{2} = {b}^{2} + {p}^{2} \\ {32}^{2} = {16}^{2} + {p}^{2} \\ 1024 = 256 + {p}^{2} \\ 1024 - 256 = {p}^{2} \\ 768 = {p}^{2} \\ \sqrt{768} = p \\ or \: p = \sqrt{768} \: ans$