Prove that (1+tan²A)Cos²A=1
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Please refer the attachment
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Answered by
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Step-by-step explanation:
(1+tan^2A)Cos^2A=1
LHS :- (1+tan^2A)Cos^2A
=1+Sin^2A/Cos^A x Cos^2A
Now do cross multiple between 1+Sin^2A/Cos^2A
=Cos^2A+Sin^2A/Cos^2A x Cos^2A
Now Cos^A Cos^2A get canceled
Then remain is
=Cos^2A+Sin^2A
=1 ............(Sin^2theta+Cos^2theta=1)
Therefore
L. H. S=R.H.S
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