Question

i

35. What part or the field remained, if sugar cane were planted in7/30
part and vegetables in 3/5part?
1)25/30 part(2)5/6 part 3)1)6 part
(4)5/7 part
show step by step​

Answer 1

Answer:

Option (3) 1/6 part

Step-by-step explanation:

Given :

Sugarcane planted in 7/30 part.

Vegetables were planted in 3/5 part.

To find :

the part of the field remained.

Solution :

Let the total field area be '1' units.

Part of field remained = total field area - planted area

⇒ Part of field remained = total field area - (sugarcane planted area + vegetables planted area)

 $\sf Part \: of \: field \: remained=1-\bigg(\dfrac{7}{30}+\dfrac{3}{5}\bigg) \\\\ \sf Part \: of \: field \: remained=1-\bigg(\dfrac{7}{30}+\dfrac{3 \times 6}{5 \times 6}\bigg) \\\\ \sf Part \: of \: field \: remained=1-\bigg(\dfrac{7}{30}+\dfrac{18}{30}\bigg) \\\\ \sf Part \: of \: field \: remained=1-\bigg(\dfrac{25}{30}\bigg) \\\\ \sf Part \: of \: field \: remained=\dfrac{30-25}{30} \\\\ \sf Part \: of \: field \: remained=\dfrac{5}{30} \\\\ \sf Part \: of \: field \: remained=\dfrac{1}{6}$

Therefore, 1/6 part of the field is remained.