i^49+i^68+i^89+i^110. Find the value of i?
Answers
Answered by
89
hey mate here is your answer
i = √-1
so i ² = -1
now i^49+i^89+i^110+i^68
(i²)^24×i+(i²)^44×i+(i²)^55+(i²)^34
(-1)^24×i+(-1)^44×i+(-1)^55+(-1)^34
i+i-1+1
2i
hope it will help you
mark me brainliest ✌✌✌
i = √-1
so i ² = -1
now i^49+i^89+i^110+i^68
(i²)^24×i+(i²)^44×i+(i²)^55+(i²)^34
(-1)^24×i+(-1)^44×i+(-1)^55+(-1)^34
i+i-1+1
2i
hope it will help you
mark me brainliest ✌✌✌
Answered by
10
Step-by-step explanation:
i^49+i^68+i^89+i^110. (i48+1)+(i64+4)+(i84+5)+(i104+6)=1i+1×1+(-1)(1)(1)=1i+1-1-1+1=1+1i=2i
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