Math, asked by ayeshanz7557, 9 months ago

ம‌தி‌ப்பு கா‌ண்க
(i) (9)^((-3)/2)
ii)(64/125)^(-2/3)

Answers

Answered by Anonymous
1

Answer:

Please ask it in English language my friend.Sure I will answer it

Answered by steffiaspinno
1

i) மதிப்பு = \frac{1}{27}  ii) மதிப்பு = \frac{25}{16}

விளக்குக:

i) (9)^{\frac{-3}{2}}

=\frac{1}{(9)^{3 / 2}}

\Rightarrow \frac{1}{\left(3^{2}\right)^{3 / 2}}

=\frac{1}{3^{2 \times 3 / 2}}

=\frac{1}{3^{3}}

=\frac{1}{27}

ii) \left[\frac{64}{125}\right]^{\frac{-2}{3}}

=\frac{\left(4^{3}\right)^{-2 / 3}}{\left(5^{3}\right)^{\frac{2}{3}}}

=\frac{4^{3 \sqrt{3}-2 / 3}}{\left(5^{3}\right)^{\frac{2}{3}}}

=\frac{4^{-2}}{5^{-2}}

=\frac{1}{4^{-2}} \times 5^{2}

=\frac{25}{16}

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