Math, asked by sanjayshinde231, 10 months ago

(i) An electric appliance of rating 300 W is used 5 hours per day in the
month of March. Find the number of units consumed.

Answers

Answered by ritikapvrchaudhary

9

Answer:

power, P = 300 W

= 300/1000 KW

Time, t = 5 hours

E = P × t

= 0.3 × 5 = 1.5 kWh

total energy consumed in march = 1.5 × 31 = 46.5 kWh

Step-by-step explanation:

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