i bought 12 boxes containing 60 mangoes each. if on an average , two mangoes from each box are spoilt, find the percentage of all the spoilt mangoea.
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Answered by
3
total no of mangoes =12 x 60=720
no of spoilt mangoes per box=2
total no of spoilt mangoes=2 x 12=24
percent of spoilt mangoes = 24/720× 100=3.334%
no of spoilt mangoes per box=2
total no of spoilt mangoes=2 x 12=24
percent of spoilt mangoes = 24/720× 100=3.334%
Answered by
4
total no.of mangoes=12*60=720
then,
spoilt mangoes =2*12=24
therefore,
percentage of all the spoilt mangoea=24/720*100=3.33%
i hope it is right answer!
then,
spoilt mangoes =2*12=24
therefore,
percentage of all the spoilt mangoea=24/720*100=3.33%
i hope it is right answer!
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