Math, asked by Tharunrai, 1 year ago

I'f tan (A+B) =
 \sqrt{3}
and (A-B)
 = 1 \div  \sqrt{3}
A+B = 90 degree. Find A and B​


Anonymous: I think you need to check the question because there's a contradiction here. Namely, can't have A+B=90 degrees AND tan(A+B) = root3
Tharunrai: they also gave A greater than B
Anonymous: The problem is that we can't have A+B=90 degrees AND tan(A+B) = root3. These are contradictory. So it's not *more* info that's needed, but *different* info.

Answers

Answered by nidhiibbani
3

a + b=60

a - b=30=b=15

a+15=60

a=60-15=45


RDEEP90: good answer
Anonymous: cico
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