Question

I
Find the missing frequency (x) of the following distribution, if mode is
34.5
0-10
Marks
obtained
10-20
20-30
30-40
18
10
No. of
​

Answer 1

Answer:

thanks for giving me free points.

Answer 2

Solution :-

Class Frequency

0 - 10 4

10 - 20 8

20 - 30 10

30 - 40 x

40 - 50 8

we know that,

• Mode = l + [(f1 - f0) / (2f1 - f0 - f2)] * h

since mode is given as 34.5 . then, modal class is 30 - 40.

so, we have,

• l = lower limit of modal class = 30
• f1 = frequency of modal class = x
• f0 = previous frequency = 10
• f2 = next frequency = 8 .
• h = size of class = 10 .

Putting all values we get,

→ 34.5 = 30 + [(f - 10)/(2f - 10 - 8)] * 10

→ 34.5 - 30 = [(f - 10)/(2f - 18)] * 10

→ 4.5(2f - 18) = 10(f - 10)

→ 9f - 81 = 10f - 100

→ 10f - 9f = 100 - 81

→ f = 19. (Ans.)

Hence, the missing frequency is 19.

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