I gram of hydrogen combines with 15.88 gram of oxygen . 8 gram of sulphur combines with 7.92 gram of oxygen . Show that these data illustrate the law of reciprocal proportions
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The law of the reciprocal :
The weights of two or more different elements which separately combines with a fixed weight of another element are either the same as or simple multiples of the weights of these elements when they combine among themselves.
HS : Hydrogen Sulphur
1 gram 15.88 gram
HO : Hydrogen Oxygen
1 gram 7.92 gram
The ratio of different weights of Oxygen (7.92) and Sulphur (15.88) Combining with the same weight of hydrogen is :
Oxygen : Sulphur
Approximately : 8 : 16 = 1 : 4
We also have :
SO : Sulphur Oxygen
8 7.92
The ratio of hydrogen(1) and Sulphur (8) reacting with equal weights of Oxygen is :
Hydrogen : Sulphur
1 : 8
From this we can see that the ratio of sulphur in this second ratio is a multiple of the first ratio.
The weights of two or more different elements which separately combines with a fixed weight of another element are either the same as or simple multiples of the weights of these elements when they combine among themselves.
HS : Hydrogen Sulphur
1 gram 15.88 gram
HO : Hydrogen Oxygen
1 gram 7.92 gram
The ratio of different weights of Oxygen (7.92) and Sulphur (15.88) Combining with the same weight of hydrogen is :
Oxygen : Sulphur
Approximately : 8 : 16 = 1 : 4
We also have :
SO : Sulphur Oxygen
8 7.92
The ratio of hydrogen(1) and Sulphur (8) reacting with equal weights of Oxygen is :
Hydrogen : Sulphur
1 : 8
From this we can see that the ratio of sulphur in this second ratio is a multiple of the first ratio.
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