Question

I have a total of Rs 300 in coins of denomination Re 1, Rs 2 and Rs 5. The number of Rs 2 coins is 3 times the pumber of Rs 5 coins. The total number of coins is 160. How many coins of cach denomination are with me?

Answer 1

Answer:

so the number of coin of 5 = 20 coins

so the number of coin of 2 = 60 coins

so the number of coin of 1 = 80 coins

Step-by-step explanation:

Let the number of coin 5 = Rs.x

so the number of coin 2 = 3x

so the number of coin 1 = 160 - 4x

so amount of rs.5 = 5x

so the amount of rs.2 = 6x

a/q

5x + 6x + 160 - 4x = 300

7x = 300 - 160

7x = 140

x = 20

so the number of coin of 5 = 20 coins

so the number of coin of 2 = 60 coins

so the number of coin of 1 = 80 coins

Answer 2

Step-by-step explanation:

x- 1rs coin

y- 2 rs coin

z- 5 rs coin

x+y+z=160

x+ 2y+5z= 300

x= 3z

so 2y+ 15z= 300

y+4z = 160.....(1)

multiply eq1 by 2

2y+8z= 320

2y+15z= 300

solving them get us -7z = 20 which is wrong..pls check que.