i have some 5rupee coin and some 2rupees coin . the no of 2rupees coin is 4times of 5rupees coin .if i have117 rupees in all, find the number of coin of each denominations
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Answered by
21
Hi friend...
Here is the solution
Let the number of 5rupee coins is x
then, 2rupee coins is 4x
now, as we have total 117 rupee so,
x(5) + 4x(2) = 117
=> 5x +8x = 117
=> 13x = 117
=> x = 117/13 = 9
Hence,
5rupee coins = 9
& 2rupee coins = 9×4 =36
_______________________
Hope it helps....
Here is the solution
Let the number of 5rupee coins is x
then, 2rupee coins is 4x
now, as we have total 117 rupee so,
x(5) + 4x(2) = 117
=> 5x +8x = 117
=> 13x = 117
=> x = 117/13 = 9
Hence,
5rupee coins = 9
& 2rupee coins = 9×4 =36
_______________________
Hope it helps....
Answered by
1
Answer:
Let the no. of 5 rupees coin is x
then, 2 rupees coin is 4x
According to the question
5(x) + 4x (2) = 117
5x +8x = 117
13x = 117
x = 117/13
x = 9
Hence,
5 rupees coin is 9
2 rupees coin is 9×4=36
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