Question

I'm not understanding the last step of the sum √2x^2+7x+5√2=0

Answer 1

√2x^2+7x+5√2=0

We will solve this using splitting the middle term method

√2 × 5√2 = 10

So we will break 7x into 5x and 2x

√2x^2+2x + 5x+5√2=0

Now we will take the common things

√2x( x + √2) + 5( x + √2) = 0

( x + √2)(√2x + 5) = 0

Now,

x + √2 = 0

x = -√2

Alpha = -√2

√2x + 5 = 0

√2x = -5

x = -5/√2

Beta = -5/√2

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Answer 2

$\sf \pmb{Answer :}$

√2x^2+7x+5√2=0

We will solve this using splitting the middle term method

√2 × 5√2 = 10

So we will break 7x into 5x and 2x

√2x^2+2x + 5x+5√2=0

Now we will take the common things

√2x( x + √2) + 5( x + √2) = 0

( x + √2)(√2x + 5) = 0

Now,

x + √2 = 0

x = -√2

Alpha = -√2

√2x + 5 = 0

√2x = -5

x = -5/√2

Beta = -5/√2

Pls mark it brainliest