Question

I'm playing card are numbered 2 to 10 a card is selecting from them at random calculate the probability that card will be an odd number​

Answer 1

here is ur answer:

total outcomes = 9

odd no = 3, 5, 7, 9

fav. outcomesb= 4

E -> card will be an odd number

$p(e) = \frac{total \: outcomes}{fav. \: outcomes} \\ \\ p(e) = \frac{4}{9}$

hope it helps you

Answer 2

$\sf\underline{Step-by-step \: explanation}$

Sample Space,

2, 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 [Total = 9]

● Odd numbers in the sample space,

● 3 , 5 , 7 , 9 [Total 4]

● Probability =

$\sf\dfrac{number \: of \: favourable \: outcomes}{number \: of \: events \: took \: place}$

● Number of favourable outcomes = 4

● Number of events = 9

● Hence, the probability will be,

4/9

● P(E) = 4/9