Math, asked by parthi93, 11 months ago

I need full Explanation

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Answered by Anonymous
0

m/(m+1)+1/(m+1)+1/(m+1)(m-1)

taking common 1/(m+1)

1/(m+1)*{(m+1)+1/(m-1)}

1+1/m^2-1

m^2/m^2-1

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