I need the derivation of pythagoras theorem . Kindly don't send the answer h^2 = b^2 + p^2 . Show me how to derive this formula . Experts do give me my answer .; I need the derivation of pythagoras theorem . Kindly don't send the answer h^2 = b^2 + p^2 . Show me how to derive this formula . Experts do give me my answer .
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What is the Pythagorean Theorem?
You can learn all about the Pythagorean Theorem, but here is a quick summary:
triangle abc
The Pythagorean Theorem says that, in a right triangle, the square of a (a2) plus the square of b (b2) is equal to the square of c (c2):
a2 + b2 = c2
Proof of the Pythagorean Theorem using Algebra
We can show that a2 + b2 = c2 using Algebra
Take a look at this diagram ... it has that "abc" triangle in it (four of them actually):
Squares and Triangles
Area of Whole Square
It is a big square, with each side having a length of a+b, so the total area is:
A = (a+b)(a+b)
Area of The Pieces
Now let's add up the areas of all the smaller pieces:
First, the smaller (tilted) square has an area of: c2
Each of the four triangles has an area of: ab2
So all four of them together is: 4ab2 = 2ab
Adding up the tilted square and the 4 triangles gives: A = c2 + 2ab
Both Areas Must Be Equal
The area of the large square is equal to the area of the tilted square and the 4 triangles. This can be written as:
(a+b)(a+b) = c2 + 2ab
NOW, let us rearrange this to see if we can get the pythagoras theorem:
Start with: (a+b)(a+b) = c2 + 2ab
Expand (a+b)(a+b): a2 + 2ab + b2 = c2 + 2ab
Subtract "2ab" from both sides: a2 + b2 = c2
DONE!
Now we can see why the Pythagorean Theorem works ... and it is actually a proof of the Pythagorean Theorem.
This proof came from China over 2000 years ago!
There are many more proofs of the Pythagorean theorem, but this one works nicely.
You can learn all about the Pythagorean Theorem, but here is a quick summary:
triangle abc
The Pythagorean Theorem says that, in a right triangle, the square of a (a2) plus the square of b (b2) is equal to the square of c (c2):
a2 + b2 = c2
Proof of the Pythagorean Theorem using Algebra
We can show that a2 + b2 = c2 using Algebra
Take a look at this diagram ... it has that "abc" triangle in it (four of them actually):
Squares and Triangles
Area of Whole Square
It is a big square, with each side having a length of a+b, so the total area is:
A = (a+b)(a+b)
Area of The Pieces
Now let's add up the areas of all the smaller pieces:
First, the smaller (tilted) square has an area of: c2
Each of the four triangles has an area of: ab2
So all four of them together is: 4ab2 = 2ab
Adding up the tilted square and the 4 triangles gives: A = c2 + 2ab
Both Areas Must Be Equal
The area of the large square is equal to the area of the tilted square and the 4 triangles. This can be written as:
(a+b)(a+b) = c2 + 2ab
NOW, let us rearrange this to see if we can get the pythagoras theorem:
Start with: (a+b)(a+b) = c2 + 2ab
Expand (a+b)(a+b): a2 + 2ab + b2 = c2 + 2ab
Subtract "2ab" from both sides: a2 + b2 = c2
DONE!
Now we can see why the Pythagorean Theorem works ... and it is actually a proof of the Pythagorean Theorem.
This proof came from China over 2000 years ago!
There are many more proofs of the Pythagorean theorem, but this one works nicely.
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