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rohit710:
what is the power in pressure ??
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21
As the values in the question is not readable , so i am taking normal values of the exponents .
This question can be easily solved by applying the equation of Boyle's law .
Here :-
P1 = 5 × 10^5
V1 = 0.25
P2 = 6 × 10^5
V2 = ?
We have to take out change in volume , that is = ( V2 - V1 )
we have to take out V2 .
Putting the values in equation , we get :
V2 =
By solving above equation , V2 = 0.208
So , V2 = 0.20. and. V1 = 0.25
Change in volume :-
=> 0.20 - 0.25
Change in volume = - 0.05
-ve sign shows that the volume has decreased.
*( Answer doesn't matter , Concepts should be strong . )
Hope It Helps You. ☺
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Ans. is B) 3.0 x 10^1 m^3 .... solution is in the pic :)
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