Physics, asked by Anonymous, 1 year ago

I need ur help...
give me solution

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rohit710: what is the power in pressure ??
rohit710: 5 × 10^ ??
rohit710: question is based on Boyle's law
rohit710: take out V2 by using Boyle's law equation and , then V2 - V1 is the change in volume

Answers

Answered by rohit710
21
\bold{Hello}

As the values in the question is not readable , so i am taking normal values of the exponents .

This question can be easily solved by applying the equation of Boyle's law .

\bold{P1V1 \:\: = \:\: P2V2}

Here :-

P1 = 5 × 10^5
V1 = 0.25

P2 = 6 × 10^5
V2 = ?

We have to take out change in volume , that is = ( V2 - V1 )

we have to take out V2 .

Putting the values in equation , we get :

V2 = \bold{\frac{5*10^{5}*0.25}{6*10^{5}}}

By solving above equation , V2 = 0.208

So , V2 = 0.20. and. V1 = 0.25

Change in volume :-

=> 0.20 - 0.25

Change in volume = - 0.05

-ve sign shows that the volume has decreased.




*( Answer doesn't matter , Concepts should be strong . )





Hope It Helps You. ☺

rohit710: Thanks for clicking brainliest :-)
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Dhinu: ye jo aapne P1 liya h wo... bulk modulus h ... pressure nhi ... aapne galat equation use kri h... and even aapka ye answer to.. options me hi nhi h!
Dhinu: haan ek min
Answered by Dhinu
4
Ans. is B) 3.0 x 10^1 m^3 .... solution is in the pic :)
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