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Dhinu:
is the answer (-137)kj/mole ??
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The enthalpy change of reaction at 298k is ...
= ∆H of C2H6 - ∆H of C2H4
= enthalpy of C2H6 - Enthalpy of C2H4
= (-85) - (52) = (-137) kj/mole ...
= ∆H of C2H6 - ∆H of C2H4
= enthalpy of C2H6 - Enthalpy of C2H4
= (-85) - (52) = (-137) kj/mole ...
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