Math, asked by parulrangari, 9 months ago

i)probability ( getting different faces on both the sides of 2 dice)
ii)probability ( sum is greater than or equal to 10 )
iii)probability (sum is less than 2)
4)probability (no. of first die is greater than second)
5) probability (sum is a perfect square)​

Answers

Answered by arpansen712
1

Step-by-step explanation:

1. 30/36 = 5/6 because there are 2 dice. so possible outputs are 6² that us 36 as both dices have 6 sides. now possibility of getting same faces in both are 1 and 1, 2 and 2, 3 and 3, 4 and 4, 5 and 5, 6 and 6. si 6 types. so we subtract 6 from 36. and are left with 30. si 30/36 that comes to 5/6.

2. outputs of greater than or equal to 10 is 4,6 5,6 6,6 6,4 5,4. si there are 5 chances thus 5/36

3. there is no probability that sum is less than 2 because even if both duces have 1 as output then also sum will be 2 and you surely know that 2 is not less than 2. and thus 0.

4. there are plenty of possibilities. viz 6,5 6,4 6,3 6,2 6,1 5,4 5,3 5,2 5,1 4,3 4,2 4,1 3,2 3,1 2,1. on counting we get 15 possible outputs. and hence 15/36 = 5/12.

5. perfect squares are 1 and 4. there is no probability or possibility that sum of sides of 2 dice will be 1 but there is chance if 4 viz 3,1 2,2 1,3. so 3 possible cases and thus 3/36=1/12.

hope you are happy and will be helped by this.

plz plz plz mark as brainliest

Similar questions