Question

ம‌தி‌ப்‌பு கா‌ண்க


i)sin30°+cos30° ii) tan60°•cot60° Iii) (tan45°)/(tan30°+tan60°)

iv) sin^2 45°+cos^2 45°

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

விளக்கம்:

$\text { (i) } \sin 30^{\circ}+\cos 30^{\circ}\\=\frac{1}{2}+\frac{\sqrt{3}}{2}\\=\frac{1+\sqrt{3}}{2}$

$\text { (ii) } \tan 60^{\circ} \cdot \cot 60^{\circ}\\=\sqrt{3} \times \frac{1}{\sqrt{3}}\\=1$

$\text { (iii) } \frac{\tan 45^{\circ}}{\tan 30^{\circ}+\tan 60^{\circ}}\\=\frac{1}{\frac{1}{\sqrt{1}}+\frac{\sqrt{1}}{1}}\\=\frac{1}{\frac{1+(\sqrt{2})^{2}}{\sqrt{1}}}$

$\frac{1}{\frac{1+1}{\sqrt{3}}}=\frac{\sqrt{3}}{4}$

$\text { (iv) } \sin ^{2} 45^{\circ}+\cos ^{2} 45^{\circ}=\left(\frac{1}{\sqrt{2}}\right)^{2}+\left(\frac{1}{\sqrt{2}}\right)^{2}$

$\frac{(1)^{2}}{(\sqrt{2})^{2}}\\=\frac{1}{2}+\frac{1}{2}\\=1$