Question

(i) The product of the ages in years) of two sisters is 238. The difference in
their ages (in years) is 3. We would like to find their present ages.​

Answer 1

Answer:

HEY BUDDY...

GOOD MORNING...♥

THEIR PRESENT AGES ARE 14 AND 17....

17 x 14 = 238...

17 - 14 = 3...

HOPE IT HELPS...!!!

HVE A GREAT DAY AHEAD...^_^

Answer 2

Answer:

17 years and 14 Years.

Step-by-step explanation:

Let the Ages of the sisters be X and Y

Given XY = 238

⇒Y = 238 / X ...................(1)

Also , X - Y = 3 ................(2)

Substituting (1) in (2)

⇒X - $\frac{238}{X}$ = 3

⇒$\frac{X^{2}- 238}{X} = 3$

⇒X² -238 =  3X

⇒X² - 3X -238 = 0

⇒X² -17X + 14X - 238 = 0

⇒X(X -17) + 14 ( X - 17) = 0

⇒(X+14) (X-17) = 0

⇒iF,(X+14)= 0

    ⇒ X = -14            Not Posssible since age cannot be Negative.

⇒iF,(X-17)= 0

    ⇒ X = 17

Substituting X = 17 IN  (2)

X - Y = 3

⇒17 - Y = 3

⇒17 - 3= Y

⇒Y = 14

Hence the Present ages of the Sisters are 17years and 14 Years.

Thank U : )