Question

I) Theorem : The opposite angles formed by two
interesting lines are of equal measure.
Given - line AB and line CD interset at pt O such
that A-O-B, C-O-D
D
A
В.
Kc
To Prove :-i) angle AOC = angle BOD
ii) angle BOC = angle AOD
Proof : angle AOC+ 0 =180 (angle in linear pair)
N + BOD = 180
)
from 1 and 2
angles AOC+ = +angleBOD
... angle AOC = angle BOD ....... eliminating angle BOC.
Similarly it can be proved that
angle BOC=
ding angles formed​

Answer 1

Answer:

58 sos its probbably not it it  was a dare to do so

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given:-

Two straight lines AB and CD intersecting at O.

To Prove:-

Vertically opposite angles are equal.

∠AOD = ∠COB

∠AOC = ∠BOD

Proof:-

We have two straight lines AB and CD intersecting at O.

∴∠AOD + ∠BOD = 180° [Straight lines] ----- 1

also,

∠COB + ∠BOD = 180° [Straight lines] ------ 2

By Euclids axiom,

Two things which are equal to a thing, is equal to each other.

Thus, eq.1 and eq.2 are equal,

∠AOD + ∠BOD = ∠COB + ∠BOD = 180°

Now, again using Euclids axiom, we can cancel out equal terms,

∠AOD + ∠BOD = ∠COB + ∠BOD

∴ ∠AOD = ∠COB

Similarly,

∠AOD + ∠BOD = 180° [Straight line] ----- 1

also,

∠AOD + ∠AOC = 180° [Straight line] ----- 2

Similarly, eq.1 and eq.2 are equal,

similarly,

∠AOC = ∠BOD

Hence proved.

Thus, when two straight lines intersect each other, they form 2 pairs of vertically opposite equal angles.

Hope it helped and believing you understood it........All the best