Question

i want answer for these questions please
this questions are from class 9

Answer 1

(I)(a) √3-1 /√3+1× √3-1/√3-1 = a-b √6. (√3 - 1 ) square / (√3) square - (1) square (√3) square+ (1) square - 2(√3)(1) / 3-1. 3+1-2√3/2. 4-2√3/2 = 2-2√3 So a= 2 b= -2 (b) 3+√7/3-√7 × 3+√7/3+√7. (3+√7) square / 3 square- √7square 3 square + √7 square + 2(3)(√7)/9-7. 9+7+6√7/2. 16+6√7 /2 = 8+6√7 So a= 8 b= 6. Question 10 - x=3+√5 X2 + 1/X2 (3+√5) square + 1/(3+√5) square 14 + 6√5 + 1/14+6√5. After rationalising the denominator. 14+6√5/1 + 14-6√5/16 224+96√5+14-6√5/16. 119+45√5/4