Question

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Answer 1

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Area below the curve of a velocity-time graph= Displacement of the object.

Displacement in 1st second= Area of the square

                                              = 1×1

                                               = 1m in first second

Displacement in 2nd second= Area of negative square

                                                = 1×(-1)

                                                = -1

$Total\:displacement= 1+(-1)$

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