Question

I want four solutions for this equation...

Answer 1

plz Mark it as brainlist

Answer 2

hiii!!!

here's ur answer...

given :- 2x + 5y = 10

=> 5y = 10 - 2x

(i) put x = 0

==> 5y = 10 - 2(0)

==> 5y = 10 - 0

==> 5y = 10

==> y = 10/5

==> y = 2

(ii) put x = -5

==> 5y = 10 - 2(-5)

==> 5y = 10 + 10

==> 5y = 20

==> y = 20/5

==> y = 4

(iii) put x = 10

==> 5y = 10 - 2(10)

==> 5y = 10 - 20

==> 5y = -10

==> y = -10/5

==> y = -2

(iv) put x = -10

==> 5y = 10 - 2(-10)

==> 5y = 10 + 20

==> 5y = 30

==> y = 30/5

==> y = 6

hence, four solutions are :- (0,2) ; (-5,4) ; (10,-2) and (-10,6)

hope this helps..!!