Question

I want to know the procedure of the 13th and 14th question

Answer 1

14.

☻KINDLY NOTE THAT I M DOING THIS QUESTION BY BOTH METHODS ☻

Method 1

In the given figure =

Total area = area of 2 trapezium

Area of trapezium = (1/2)(sum of parallel sides)*(Perpendicular height )

Area = (1/2)*(32+18)*(9)

= (1/2)*(50)*(9)

= Area of 2 Trapezium = 2*(1/2)*50*9

= 50*9

= 450 -------------(i)

Method 2 RAHUL GANDHI'S METHODS ☻☻☻

Area of Figure = Area of Square + Area of 2 Right angled Triangle

Area of Square = A*A

A= 18

Area = 18*18

= 324

Area of 2 Right angled triangle

= 2*(1/2)*(14)*(9)

= 14*9

= 126

Total Area = 324+126 = 450 ---------- (ii)

Area i = Area ii

450 = 450

Hope you understand

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