I want to simplify 101×99 using distributive property of multiplication of integers
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Answered by
31
101×99
=(100+1)(100-1)
=100^2-1^2
=10000-1
=9999
=(100+1)(100-1)
=100^2-1^2
=10000-1
=9999
Answered by
18
101×99=
(101×90)+(101×9
= 9999
(101×90)+(101×9
= 9999
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