Question

I want to verify the answer of this question is it 12-2root35/2.If it is wrong plzz show me how to

Answer 1

Heya user!!!

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The solution is as follows;-

(√7-√5)*(√7-√5)/(√7+√5)*(√7-√5)

{multiplying denominator and numerator without (√7-√5)...

=(√7-√5)²/7-5. (a+b)*(a-b)=a²-b²

=7+5-2√35/2. (a-b)²=a²+b²-2ab

=12-2√35/2

=6-√35......

This is the answer!!!

U had done correct ...

Just do one step more ..........take 2 as common in both numerator and denominator......

Answer 2

$Given : \frac{ \sqrt{7} - \sqrt{5} }{ \sqrt{7} + \sqrt{5} }$

$= \ \textgreater \ \frac{ (\sqrt{7} - \sqrt{5} )( \sqrt{7} - \sqrt{5}) }{( \sqrt{7} + \sqrt{5})( \sqrt{7 - \sqrt{5} } ) }$

$= \ \textgreater \ \frac{( \sqrt{7} - \sqrt{5} )^2}{( \sqrt{7} )^2 - (5)^2}$

We know that (a - b)^2 = a^2 + b^2 - 2ab.

$= \ \textgreater \ \frac{7 + 5 - 2 \sqrt{35} }{7 - 5}$

$= \ \textgreater \ \frac{12 - 2 \sqrt{35} }{2}$

$= \ \textgreater \ 6 - \sqrt{35}$




Hope this helps!