I will mark as you a brainlest solve if the sum of roots of quadratic equation is 3 and the sum of their cubes is 63, find the quadratic equation
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Answer:
the sum = 3. and the product = -6. ==>
Step-by-step explanation:
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roots is αβ
so,
α+β=3
α^3+β^3=63
(α+β)(α^2-αβ+β^2)=63
3*(9-3αβ)
27-9αβ=63
36=-9αβ
-αβ=4
αβ=-4
so, equation is
x^2-(α+β)x+αβ
x^2-(3)x-4
x^2-3x-4
plz mark me as brainliest
so,
α+β=3
α^3+β^3=63
(α+β)(α^2-αβ+β^2)=63
3*(9-3αβ)
27-9αβ=63
36=-9αβ
-αβ=4
αβ=-4
so, equation is
x^2-(α+β)x+αβ
x^2-(3)x-4
x^2-3x-4
plz mark me as brainliest
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